sin[(2n 1)𝛑 - theta] = sin theta

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Formulas 'sin(2npi + theta) = sin theta' and 'sin[(2n+1)pi - theta] = sin theta'

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sin(nπ)=0 and cos (2n+1) π/2 = 0 | Explained with unit circle

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Z = Cis (theta) then Z^(2n) - 1 / Z^(2n) + 1 = i tan n(theta)@EAG

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If z = cos θ + i sin θ then z^n+1/z^n = 2 cos nθ and z^n -1/z^n = 2 i sin nθ || Complex Numbers

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Trigonometric Values 0, π/2, π, 3π/2, 2π,⋅⋅⋅ at Lightning Speed

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Graph of sine and cosine. sin(nπ) = 0 and cos{(2n+1)π/2} = 0

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Sign of Trigo.Ratios as well as sin θ = 0 (θ = nπ) & cosθ = 0 [θ =(2n+1)π/2] n∈Z-Pranesh Kumar Sir

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The Continuum of Knowledge: Advanced Mathematical Contributions of Bharat

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The value of `sintheta + sin3theta +sin5theta + '…..'+ sin(2n-1)theta` is

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If `I_n=int_0^(pi/2) (sin(2n-1)x)/sinx)dx`, and `a_n=int_0^(pi/2) ((sinntheta)/sintheta)^

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Prove that `sintheta+s in3theta+sin5theta++sin(2n-1)theta=(sin^2ntheta)/(sintheta)dot`

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sin^2m+1 cos^2n+1 integration directly

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(1+ i)^2n + (1-i)^2n = 2^n+1 Cos(n pi /2) ; De-Movire's theorem@EAG

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For any `n in N, int_(0)^(pi) (sin (2n+1)x)/(sinx)dx` is equal to

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Prove that β(m,n) = 2 × Integral (sinθ)^2m-1 (cosθ)^2n-1 from 0 to π/2 | Beta Functions

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Sum m from 1 to 2n-1 of sin(π m²/2n)/sin(π m/2n)

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Trigonometric functions ( quadrant angle cos (2n+1)π/2=0)

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7#DeMoivre's Theorem If Z = CiS θ then show that [Z^(2n) - 1] / [Z^(2n) + 1] = i Tan(nθ)

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sin(-theta)=-sin theta proof | sin minus theta is equal to minus sin theta

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28) Show that (1+i)^2n +(1-i)^2n = 2^n+1 Cos nπ/2 || Demoivre's Theorem || 7 Marks Problem

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🤣Modi ji ne to math ki esi taisi kar diye🤣🙆🏻‍♂️ #shorts #youtubeshorts #viral

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#09 problem of complex number | prove that ((1+cosθ+i sinθ)/(1+cosθ-i sinθ))^n= cos⁡nθ+i sin nθ

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IIT JEE TRIGONOMETRIC FUNCTIONS Let `f(theta)=sintheta(sintheta+sin3theta)dot` Then `f(theta)` i...